Please help me derive this equation
Please help me derive this equation 3RT 1.3 Derive the root-mean-square speed of a gas, Vrms...
Vrms=√3RT/M In this root mean square velocity formula, Why and Where does this '3' came from. Could you explain and give me a nice derivation.
The root-mean-square speed of the molecules in a gas in an indication of the temperature of this gas. Shown below is the spectrum of three stars of different surface temperature. The x-axis displays the wavelength of the light emitted by the star. Shorter wavelength corresponds to higher energy of the gas, longer wavelength to lower energy. Stars are primarily made of Hydrogen. Calculate vrms for the three stars shown in the figure. How do these values compare to the rms...
Calculate the root mean square velocity, vrms, of a molecule that has a molar mass, M, of 45.02 g/mol at a temperature of 40.56 °C using the equation below. For this calculation the gas constant, R, is expressed as 8.314 J/(mol*K) and the molar mass, M, needs to be converted to kg/mol. vrms=3RTM
the root-mean-square speed(Urms)is the speed of gas particles possessing the average kinetic energy (KE) which is mathematically defined by the following two equations KE=NA(1/2mu2) KE=3/2RT Given that NA•m=M, where NA is Avogadro's number, m is mass and M is molar mass use algebra to derive the equation for Urms
The root-mean-square speed (thermal speed) for a certain gas at 100 degree C is 0.500 km/s. If the temperature of the gas is now increased to 200 degree C, the root-mean-square(thermal) speed will be closest to 563 m/s. 1000 m/s 634m/s 707 m/s 804 m/s
Compute the root-mean-square speed of Ar molecules in a sample of argon gas at a temperature of 191°C.
Compute the root-mean-square speed of Ar molecules in a sample of argon gas at a temperature of 175°C. ms!
Calculate the root mean square speed for a sample of neon gas (Ne) at 298K. Your answer should have three significant figures. Use R=8.314 J/(K mol).
A certain gas sample has following speed distribution. The root mean square speed of this distribution is y=f(v) V(m/s) 250 450 380 m/s O a. 400 m/s Ob. 348 m/s 355 m/s O d.
PLEASE PLEASE HELP! Calculate the root mean square velocity and kinetic energy of CO, CO2, and SO3 at 298 K Part A. Calculate the root mean square velocity of CO at 298 K . Part B. Calculate the root mean square velocity of CO2 at 298 K . Part C. Calculate the root mean square velocity of SO3 at 298 K . Part D. Calculate the kinetic energy of CO at 298 K . Part E. Calculate the kinetic energy...