Suppose an experiment is performed with ultracold neutrons having velocities of 1.05 m/s.
A) What is the wavelength of such a neutron, in nanometers?
B) What is its kinetic energy, in electronvolts?
Solution)
Given,
Velocity,v=1.05 m/s
Here, Momentum, P=mV=(1.675*10^-27 kg)*(1.05)
P=1.75*10^-27 kg-m/s
Now, lambda=h/P=(6.626*10^-34)/(1.75*10^-27)=3.76*10^-7 m
=376.74 nm(Ans)
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Part b)
Kinetic Energy, KE=P*V/2=(1.75*10^-27)*(1.05)/2=9.18*10^-28 J
=5.74*10^-9 eV (Ans)
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