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Two 1.8 kg bodies, A and B, collide. The velocities before the collision are A = (12 + 25) m/s and B = (-10 + 10.0) m/s....

Two 1.8 kg bodies, A and B, collide. The velocities before the collision are vector vA = (12i hat + 25j) m/s and vector vB = (-10i hat + 10.0j) m/s. After the collision, vector v'A = (-1.0i hat + 22j) m/s.

(a) What is the final velocity of B?
v with arrow =  

m/s

(b) What is the change in the total kinetic energy (including sign)?
J

0 0
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Answer #1


MAEMB = 18 kg VAXT = 12 m / sec; Vagy = 25m/sec Vaxy = -1 m/see; Vay= 22 m/sec VB2: • -10 m/sec VBy: = 10 m/sec. a) conservat

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Two 1.8 kg bodies, A and B, collide. The velocities before the collision are A = (12 + 25) m/s and B = (-10 + 10.0) m/s....
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