1-Dimensional INELASTIC Collision: A 1-kg mass traveling from left to right at 10.0 m/s hits and...
1-Dimensional INELASTIC Collision: A 1-kg mass traveling from left to right at 10.0 m/s hits and STICKS to a 6.00 kg mass that was travelling from right to left at 10.0 m/s.
a) What is the final velocity (speed and direction) of the combined mass after the collision?
b) How much KINETIC ENERGY has been LOST in this collision?
c) Where did that lost energy go?
Homework Answers
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1-Dimensional INELASTIC Collision: A 1-kg mass traveling from
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A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds...
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Energy Lost in Inelastic Collision Difficult Accuracy 0% 4 m/s 8 m/s 3 kg 2 kg Created for Albertio. All rights reserved 2016 The above diagramshows the motion and masses of two carts before a collision in a student experiment (Friction can be considered neglable in this experiment) After the collision the cat is moving back to the left at 2 m/s How much kinetic energy is lost during this inelastic colision? Elimination Tool 39] C 57J D 81J
2. In a completely inelastic collision, a 500 traveling west at 10 m/s. kg car traveling east at 30 m's hit a 2000 kg truck a. At what speed and in what direction will the joined car/truck go after the collision? b. Calculate the kinetic energy of the car before the collision. c. Calculate the kinetic energy of the truck before the collision. d. Calculate the kinetic energy of the joined car and truck together after the collision. e. How...
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9. A 2-kg mass moving to the right at 5m/s collides with and sticks to a 1-kemas to the left at 4 m/s a. Determine the final velocity of the combined masses. Emizeme 30=6 mivem V2 = v= 2 m/s (2)(5) H1) (-4):308 10-4 =3v b. Calculate the initial kinetic energy of the two mass system c. Calculate the final kinetic energy of the two mass system. d. Calculate how much mechanical energy was lost in the collision. Where did...
A 6.00 kg bowling ball moving at 10.0 m/s collides with a 1.60 kg bowling pin, scattering it with a speed of 8.00 m/s and at an angle of 38.5 with respect to the initial direction of the bowling ball (*) Calculate the final velocity (magnitude in mys and direction in degrees counterclockwise from the original direction of the bowling ball magnitude m/s direction counterclockwise from the original direction of the bowing ball (b) Ignoring rotation, what was the original...
Two particles of mass m1 = 2.0 kg and m2 = 2.6 kg undergo a one-dimensional head-on collision as shown in the figure below. Their initial velocities along x are vii = 15 m/s and v2,--6.8 m/s. The two particles stick together after the collision (a completely inelastic collision. (Assume to the right as the positive direction.) mi m2 (a) Find the velocity after the collision. 2.6782 m/s (b) How much kinetic energy is lost in the collision? 153.907x
A6.65 kg bowling bal moving at 10.0 m/ s colides with a 1.60 kg bowling pin, scattering It with a speed of 8.00 m/s and at an angle of 36.0% with respect to the initial direction of the (a) Calculate the final velocity (magnitude in m/s and direction in degrees velocity (magnitude in m/s and direction in degrees counterclockwise from the original direction) of the bowling ball magnitude m/s direction counterdlockwise from the original direction of the bowling ball (b)...
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds itself in a block of mass 4 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? Vf = m/s ) Calculate the total translational kinetic energy before and after the collision. Ktrans,i = Ktrans,f = (c) Compare the two results and explain why there is a...
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds itself in a block of mass 5 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? Vr = 42 x m/s (b) Calculate the total translational kinetic energy before and after the collision. Ktrans,i = 374.85 Ktrans,f= (c) Compare the two results and explain why there...
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