Question

A 6.00 kg bowling ball moving at 10.0 m/s collides with a 1.60 kg bowling pin, scattering it with a speed of 8.00 m/s and at an angle of 38.5 with respect to the initial direction of the bowling ball (*) Calculate the final velocity (magnitude in mys and direction in degrees counterclockwise from the original direction of the bowling ball magnitude m/s direction counterclockwise from the original direction of the bowing ball (b) Ignoring rotation, what was the original kinetic energy in joules of the bowling ball before the collision? (c) Ignoring rotation, what is the final kinetic energy in joules of the system of the bowling ball and pin after the collision? (d) is the collision elastic or inelastic? elastic inelastic

Answer 1

ball Pin e38So - lo m1s VSine All the given data is shown in figure above No external force is acting on the system So momentum remains conserved Pinitial = Pfinal from momentum conservation in horizontal direction m1u10m U1 cos + m2U2 cos0 6 x 10 61 cosp +(1.6) x (8) x cos (38.5) U1 cos 8.331 from momentum conservation in vertical direction 0 m1 sin-m2 U2 sin0 0 61 sin (1.6) x (8) x sin (38.5) U1 sin 1.328 v1 = V8.3312 + 1.3282 U1 = 8.436 x m/s

-1 1.328 8.331 p tan p = 1.618 Original KE KEo mum2 KEo mu+0 KEg(6)x (10) = 300J Final kinetic energy +x (6) x (8.436 KE, = x(1.6)x (8 КЕ, = 264.7J Since kinetic energy is not conserved therefore collision is inelastic