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A 7.05-kg bowling ball moving at 10.0 m/s collides with a 1.60-kg bowling pin, scattering it...

A 7.05-kg bowling ball moving at 10.0 m/s collides with a 1.60-kg bowling pin, scattering it with a speed of 8.00 m/s and at an angle of 34.5° with respect to the initial direction of the bowling ball.

Calculate the final velocity (magnitude and direction) of the bowling ball?

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Answer #1

The initial momentum is, pmv (7.05 kg (10m/s) 70.5 kg.m/s The x component of momentum in x direction is pr-mv cos θ-(1.60 kg)(8 m/s)cos 34.5°-10.55 kg.m/s p, mv sin θ ( 1.60 kg)(8 m/s )sin 34.5°-7.25 kg.m/s The x component of the balls final momentum is p P-P-70.5 kg.m/s-10.55 kg.m/s-59.95kg.m/s So, the x component of velocity is 59.95 kg.m/s 7.05 kg Since initially the ball is moving in the positive x direction, it had no y component of momentum. So, the sum of the momentum of the y direction must be zero So, the y component of momentum is

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