Question

Problem 10: A 5.5-kg bowling ball moving at 9.4 m/s collides with a 0.875-kg bowling pin, which is scattered at an angle of θ = 24° from the initial direction of the bowling ball, with a speed of 10.4 m/s.

Part (a) Calculate the direction, in degrees, of the final velocity of the bowling ball. This angle should be measured in the same way that θ is. Numeric : A numeric value is expected and not an expression. θb = __________________________________________

Part (b) Calculate the magnitude of the final velocity, in meters per second, of the bowling ball. Numeric : A numeric value is expected and not an expression. v'1 = __________________________________________

Answer 1

A)

Tan(theta) = - (m2 v2 sin(theta_2))/(m1v1 - m2v2 cos(theta_2))

Tan(theta) = - (0.875 x 10.4 sin(24))/(5.5 x 9.4 - 0.875 x 10.4 cos(24))

Theta = - 4.88 degree

B)

Velocity, v = - (m2 v2 sin(theta_2))/(m1 sin(theta_1))

V = - (0.875 x 10.4 sin(24))/(5.5 cos(-4.88)) = 0.68 m/s

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