Number of moles of AgNO3 = molarity * volume of solution in L
Number of moles of AgNO3 = 0.67 * 0.0166 = 0.0111 mole
From the balanced equation we can say that
2 mole of AgNO3 requires 1 mole of Cu so
0.0111 mole of AgNO3 will require
= 0.0111 mole of AgNO3 *(1 mole of Cu / 2 mole of AgNO3)
= 0.00555 mole of Cu
mass of 1 mole of Cu = 63.546 g so
the mass of 0.00555 mole of Cu = 0.35 g
Therefore, the mass of Cu required would be 0.35 g
Question 10 Consider the balanced equation representing the reaction of solid copper and aqueous silver nitrate:...
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