Question

part b only please

Part A The position of the particle is given by (0.563t2-4.50t 6) m, where t is in seconds. Determine the time when the velocity of the particle is zero. Express your answer to three significant figures and include the appropriate units Figure 1) t4.00 s US swe Correct Part B igure 1 of 1 Determine the total distance traveled by the particle when t 6.31 s Express your answer to three significant figures and include the appropriate units. AsValue Units SubmitPr Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining

Answer 1

here we have

s=0.563t²-4.5t+6...................eqn 1)

so V=ds/dt=1.126t-4.5

so when v=0

1.126t-4.5=0

t=4.00s

part B) total distance

ds/dt$\rightarrow$0

here we have t=0, t=4, t=6.31

now using equation 1

when t=0, s=6

when t=4,s=-3

when t=6.31 s=0

from 0-4 s $\Delta$s=9m

from 4-6.31s $\Delta$s=3m

so total distance =9+3=12.0m

so answer is 12.0 m