Question

Review MISSED THIS? Read Section 44(Pages 149-155) Watch KCV 4 4. WE 46 Elemental phosphorus reacts with chlorine gas according to the equation P.(s) + 6C ( -4PCI(1) A reaction mixture initially contains 45 27P and 130.5 g Cl Part A of the excessa ris Once the reaction has reached completion what mass in Express the mass in grams to three significant figures. View Available Hints) O AE = om? Sub

Answer 1

mars of Pu = 45.27 g molar mass of Pu= 123.9 gimol moles of Pue mass o molar mass = 0.365 mol mass of clea = 130.5g Molare mass of cl = 70.9 gineal moles of Cl2 = 130.5 = 1.842 moles 70.9 I mole Py macts with 6 moles Cla i for 0.365 mol Pu, noul of ll required Tawal = 0.365x6 = 2.19 moles moles of cle read> moles of cla available rence , cl acts as limiting reagent is moles of Pu consumed = 1.841 = 0·307 mol Remaining Pu moles = 0.365-0.307 = 0.058 mol mass = moles x molar mass mass of Py = 0.058 mol x 123.9 que имое mass of Pu left = 7.186 g