Given that, sample size ( n ) = 14
sample mean = $19850
sample standard deviation ( s ) = $1184
The null and alternative hypotheses are,
Q.12) Test statistic is,
t.s. = -2.05
Answer: e) none of these
Q.13) t-scores ( tc) for the two tailed test at with df = 14 -1= 13 is, tc = +/- 2.16
Answer: b) +/- 2.16
Q.14) t-scores ( tc ) for the two tailed test at with df = 14 - 1 = 13 are tc = +/- 3.01
Answer: b) +/- 3.01
Q.15)
t.s. = -2.05 > -2.16
So, we fail to reject the null hypothesis ( H0).
t.s. = -2.05 > -3.01
So, we fail to reject the null hypothesis ( H0).
Answer: d) FTR H0 at and
sample 14 similar cars and find a mean price of $19,850 with a standard deviation of...
Questions 12-15:A dealer claims that the price of a car is $20,500 You think that's wrong so yo sample 14 similar cars and find a mean price of $19,850 with a standard deviation of $1184 Find the test statistic (t.s.) for your sample. (the formula is: 1 a)2.24 b)-2.24 c)-16 d) .16 e) none ofthese Find the critical t-score (t) for the two tailed test with α-05. , a) ±1.96 b) ±2.16 c) ±1.77 d) ±1.76 e) none of these...
#12-#15 A dealer claims that the price of a car is $20,500. You think that's high so you sample 14 similar cars and find a mean price of $19,850 with a standard deviation of $1084. - e) none 1.77 d) -1.76 e) none 12. Find the test statistic (t.s.) for your sample using the formula -2.24) -16 d) .16 13. Find the critical t-score (t) for the left tailed test with a .05 and d.f.-13. 2.24 a) -1.96 b) -2.16...
Find the critical t-score (t) for the two tailed test with α-.01. a) t2.58 b) t3.01 c2.62 d) 2.65 e) none of these 14. 15.Therefore, the conclusion for this hypothesis test is: a) reject Ho at a-.05 and FTR Ho at a-o1 c) reject H° at α-.01 and FTR Ho at α-05 b) reject H, at α-.05 and α-.01 d) FIR h, at α-.05 and α-,01 e) none of these after in the percentage of cans showing discoloration 16. This...
c) reject Ho at α .01 and 1 R Ho at α- d) F 1 R Ho at α-.05 and α-.01 e) none of these Question 16 0: Typically 10% o cars o fruit prepar du ingth current proces reduco oration afier 90 days. In arandom sample of 225 cans prepared with a new process, 12 show discoloration after 90 days. Perform an hypothesis test at α-.01 to de in the percentage of cans showing discoloration termine if the new...
Questions 16-20: Typically 10% ofcans offruit prepared usingthe currentprocess how discoloration after 90 days, In a random sample of 225 cans prepared with a new process. 12 show discoloration afier 90 days Perform an hypothesis test at a01 to determine if the new process makes a difference in the percentage of cans showing discoloration 16. This hypothesis test is a involving a population a) ITT, mean b) ITT, proportion c) 2TT, mean d) 2TT, proportion e) none of these The...
Given a sample of 20 students with a mean LQ. of 107 and s a) (99.55, 114.45) b) (97.21, 116.79) c) (96.13, 117.88) 17, find the 95% CL: d) (99.04, 114.96) e) none of these In a survey of 600 people with 317 claiming they would vote yes, find and interpret the 99% CL a) we are confident that the proportion of yes voters is .5283 b) we are sure of 317 yes votes c) we know that the proportion...
please answer 38, thanks. 26. Given a test statistic of 2.09 paired with a crtical z-score of 2 33 on a one tailed test, then the conclusion fail to reject H. at α-1% b)fail to reject H,at α-5%e reject KedacceptH,ata-1% d) reject, and accept H. at a " 5% At a 95% a) e) nooc of these 27. interval, how often would we expect u to 5% 95% c)1% fall outside the inerval estimate? 28. We are allowed to use...
A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, μ, of the population from which the sample was drawn. Use the critical-value approach. 7. x-20.8, s-7.3>, n = 11, Ho: μ = 18.7, Ha: μ # 18.7, α = 0.05 a. Test statistic: t = 0.95. Critical values: ±1.96. Reject Ho. There is sufficient evidence to b. Test statistic: 0.95. Critical values: t = ±2.201....
Find the critical value of t from Appendix D for the following situations. Specify the correct degrees of freedom, whether the value is “+/-“ or is “+ or –“ and the df you used in the table if the value isn’t listed. a) N = 32, α = .05, one-tailed independent groups t-test b) N = 28, α = .01, two-tailed independent groups t-test c) N = 26, α = .05, one-tailed independent groups t-test d) N = 41, α...
1. Sample Mean: mens- 27.91 women - 31.57 2. Standard Deviation men- 0.664 women- 1.167 Sample Size mens- 32 womens- 35 Using the values that you found in numbers 1 and 2, perform the following hypothesis test. At a 10% significance level, test the claim that the women’s mean completion time is greater than ___________ (the men’s mean completion time). Ho: _________________ Ha: __________________ Label the claim. What type of test will you use? (Z-Test, T-test, or 1-ProZTest) ____________________ Where...