Question

1. Sample Mean: mens- 27.91 women - 31.57 2. Standard Deviation men- 0.664 women- 1.167 Sample...

1. Sample Mean:

mens- 27.91

women - 31.57

2. Standard Deviation

men- 0.664

women- 1.167

Sample Size

mens- 32

womens- 35

  1. Using the values that you found in numbers 1 and 2, perform the following hypothesis test.

At a 10% significance level, test the claim that the women’s mean completion time is greater than ___________ (the men’s mean completion time).

  1. Ho: _________________   Ha: __________________ Label the claim.
  2. What type of test will you use? (Z-Test, T-test, or 1-ProZTest) ____________________
  3. Where is the rejection region? (Left-tailed, Right-tailed, Two-tailed test) _____________
  4. Find the critical value(s). α = 0.10 ________________
  5. What is the value of the standardized test statistic? _________________
  6. What is your p-value? __________________
  7. What is your decision? (Reject Ho or Fail to Reject Ho) _________________
  8. Write your conclusion.
    There ____________ (is/is not) enough evidence to ______________ (support/reject) the claim that _________________.
0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
1. Sample Mean: mens- 27.91 women - 31.57 2. Standard Deviation men- 0.664 women- 1.167 Sample...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 9. Using the values that you found in numbers 1 and 2, perform the following hypothesis...

    9. Using the values that you found in numbers 1 and 2, perform the following hypothesis test. At a 10% significance level, test the claim that the women’s mean completion time is greater than ___________ (the men’s mean completion time). Use the samples to find the mean completion time of the for the male runners- 29.91 female runners- 31.57 Use the samples to find the sample standard deviation of the completion times for the male runners- .66 female runners- 1.17...

  • _ 9) In a sample of 10 randomly selected women, it was found that their mean height was 634 inches. From previous...

    _ 9) In a sample of 10 randomly selected women, it was found that their mean height was 634 inches. From previous studies, it is assumed that the standard deviation, , 124 inches and that the population of height measurements is normally distributed a) Construct the confidence interval for the population mean height of women b) If the sample size was doubled to 20 women, what will be the effect on the confidence interval? 10) 10) The numbers of advertisements...

  • V2 Given in the table are the BMI statistics for random samples of men and women....

    V2 Given in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. P1 40 28.4029 7.020534 X 40 24.8792 4.562776 5 OC. Hoy H2 HH1 H2 D. Ho: 11 12 на: 4 #2 The test statistic,...

  • Given in the table are the BMI statistics for random samples of men and women. Assume...

    Given in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. n Male BMI Female BMI 1 12 50 50 27.5997 25 6435 8.819325 4.764227 X S a. Test the claim that males and females have...

  • Given in the table are the BMI statistics for random samples of men and women. Assume...

    Given in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Male BMI Female BMI μ μ1 μ2 n 45 45 x 27.3958 24.7599 s 7.837628 4.750044 a. Test the claim that males and females have...

  • u A study was done on body temperatures of men and women. The results are shown...

    u A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts Men 11 11 97.76°F 0.81°F Women 2 59 97.45°F 0.71°F S a. Test the claim that men have a higher mean...

  • A researcher claimed that a higher proportion of women than men exercise regularly. A random sample...

    A researcher claimed that a higher proportion of women than men exercise regularly. A random sample of 150 men found that 88 of the men exercise regularly, while a random sample of 200 women found that 130 of the women exercise regularly. Test this claim using a significance level of 0.01. What is the z-stat? What is the p-value? What is your decision for the hypothesis test above? Retain or reject Ho? Please write a statement that summarizes your findings...

  • 1. A random sample of 200 observations indicates a sample mean of 4117 with a standard...

    1. A random sample of 200 observations indicates a sample mean of 4117 with a standard deviation of 300. Test the hypothesis that the mean is greater than 4100 at alpha = 0.01. Group of answer choices Ho: μ ≤ 4100, Ha: μ > 4100; critical value -2.33, z= -0.92, fail to reject Ho. Ho: μ ≤ 4100, Ha: μ > 4100; critical value -2.33, z= -2.34, reject Ho. Ho: μ ≤ 4100, Ha: μ > 4100; critical value -1.96,...

  • A company claims that the mean monthly residential electricity consumption in a certain region is more...

    A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 64 residential customers has a mean monthly consumption of 910 kWh. Assume the population standard deviation is 121 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and Ha. Choose the correct answer below. O B. Ho u...

  • d. Determine the sample mean and sample standard deviation of the Blood Glucose for both men...

    d. Determine the sample mean and sample standard deviation of the Blood Glucose for both men and women. Test the claim that the average mean Blood Glucose of women is different from the average mean Blood Glucose of men. Use α = 0.01. Hint: It would be helpful to sort the data based on gender. (8 points) Mean Glucose Female Standard Deviation Glucose Female Sample Size Female Mean Glucose Male Standard Devation Male Sample Size Male Hypotheses Test Statistic Critical...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT