Question

Using available experimental data on the exchange current densities, calculate the area-specific charge transfer resistance of dissolution of Cd(s) in [0.01 mol/L CdSO₄(aq) + 0.4 mol/L K₂SO₄(aq)] solution at 25 °C.

Answer 1

For this question charge transfer resistance for cadmium is given by

Cd = (1- $\beta$ ) (1/j₀ + 1/j₀⁰) (j₀ + j₀⁰)

Cd = (1-0.45) [(1/1.5 * 10^-3 )+ (1 / 1.9 * 10^-2)] * [(1.5 * 10^-3) + (1.9 * 10^-2)]

Cd = 0.55 * 719.2982 * 0.0205

Cd = 8.11

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