What is the volume occupied by 0.251 mol of helium gas at 1.35 atm and 307 K ?
Given:
P = 1.35 atm
n = 0.251 mol
T = 307 K
use:
P * V = n*R*T
1.35 atm * V = 0.251 mol* 0.08206 atm.L/mol.K * 307 K
V = 4.6839 L
Answer: 4.68 L
What is the volume occupied by 0.251 mol of helium gas at 1.35 atm and 307...
What is the volume occupied by 0.249 mol of helium gas at 1.17 atm and 309 K ?
What is the volume occupied by 0.255 mol of helium gas at 1.25 atm and 305 K?
What is the volume occupied by 0.247 mol of helium gas at 1.27 atm and 308 K ?
What volume is occupied by 0.103 mol of helium gas at pressure of 0.94 atm and a temperature of 310 K?
What is the volume occupied by 0.246 Imol of helium gas at 1.24 atm and 309 K ?
A tank of volume 0.438 m3 contains 1.35 mol of helium gas at 52 ◦C. Assume that the helium behaves like as an ideal gas. The universal gas constant is 8.31451 J/K mol, and Boltzmann’s constant is 1.38066 × 10−23 J/K. What is the average kinetic energy per molecule? Answer in units of J
Find the volume occupied by 28.0 g of helium gas at 24.0 ∘C and 1.26 atm of pressure.
What is the volume occupied by 1.000 mol of nitrogen gas at a pressure of 2.00 atm and a temperature of 100 K? Gas constant R = 0.08206 L.atm. mol.
CHapter TI AW Exercise 11.59 Part A What is the volume occupied by 0.256 mol of helium gas at 1.20 atm and 309 K? VAD ? V = L Submit Request Answer Provide Feedback
Use the ideal gas law to calculate the volume occupied by 0.600 mol of nitrogen gas at 5.00 atm pressure and at 27°C. R = 0.0821 L* atm/(K * mol).