Question

CHapter TI AW Exercise 11.59 Part A What is the volume occupied by 0.256 mol of helium gas at 1.20 atm and 309 K? VAD ? V = L Submit Request Answer Provide Feedback

Answer 1

Given 8- wo. of moles = 0.256 pressure - 1.20 atm temperature = 309k we know that ! - Lihhed PV = nRT , where, &P= Pressure on de volume na no. Of moles Anore on R = 0.082 Lahm K not Petting the values of Pin and & in the equation we get - N Pue nRT -) 1-20 X NS 0-257 x 0.082 X 309 at 1.20x v= 6.486 ) v 6. 486 L 1-20 V 5.405 L e volume gas Thus, the of Helium 5.405 L occupied by 1.20 aton 0.256 vnd and 3ook at s