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Chapter 5 Exercise 5.42 Part A What is the temperature of 0.65 mol of gas at a pressure of 1.4 bar and a volume of 10.7 L Exp
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Answer #1

PV= nRT

where, P = pressure = 1.4 bar = 1.38 atm

V = volume = 10.7 L

n = number of moles = 0.65 mol

R = Gas constant

T = temperature = ?

1.38 * 10.7 = 0.65 * 0.0821 * T

14.8 = 0.0534 * T

T = 14.8 / 0.0534 = 277 K

Therefore, temperature of gas = 277 K

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