Homework Answers
I am attaching the t table below
You can see that against 24 degree of freedom and at 0.001 level of significance the t value is 3.745 which implies that if our t calculated value is 3.74 then p value would be 0.001.
But here t calculated value is 13 which is obviously much much lower than 0.001.
So clearly , here p-value < 0.1 and hence we have enough
evidence to reject our null hypothesis at 10% level of
significance.
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