Question

According to a survey, the average American person reads for 3 hours per week. To test if the amount of reading in Chicago is more than the national average, a researcher decides to do a hypothesis test, at a 5% significance level. She surveys 17 Chicagoans randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 3.4 hours per week, and the sample standard deviation (s) is 0.8 hours.

• H0: μ≤3; Ha: μ>3.
• α=0.05 (significance level)

What is the test statistic (t-value) of this one-mean hypothesis test (with σ unknown)?

• Round your final answer to two decimal places.

Provide your answer below:

Test Statistic=?

Answer 1

Test statistic,
t = (xbar - mu)/(s/sqrt(n))
t = (3.4 - 3)/(0.8/sqrt(17))
t = 2.06

P-value Approach
P-value = 0.0280
As P-value < 0.05, reject the null hypothesis.