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bis 26.8 a distancu solve €500 A [12] 14. The figure shows a cross section of a 200 m long solid cylindrical conductor whose
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R=0.268M, I = 300 A, PE 0.15m Current density, J- I NR2men en using Amperes law & Bodd=4. Tin Tin = 5x3772 Irland (LT) R? (

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