Question

SOO A 21 14. The figure shows a cross section of a 200 m long solid cylindrical conductor whose us is 26.8 cm. It carries a uniform current of 500 A. Using Ampere's Law, determine the magnetic field at a distance of 9.00 cm from the center. Hint: You need to calculate the current density to help you solve the problem. If you show your work in an organized, and clear manner that I can see that you are working the problem correctly and not just writing from the memory of some problem that was previously worked out, you will get partial credit depending on how correct you work is. Direction: Answer: (Magnitude)

Answer 1

Direction of magnetic field will be circular at distance r from axis of cylinder.

Son L = 200m, R= 0.268 m, I = 500 A , P=0.09 m Current density, J- I - 500 0=2215.90 Alm2 JIR? rx (0.268) 2 . Using Ampere's circuital lew. spore $ 8.de = M. Tin Iin = Jx1772 - 2215.90*5*0.0902 1. Iin= 56.39 A Bx208=M.Iin B = M. I in 208 = 4x1077 x 56.39 20*0.09 | B - 1.253410-41