Question

'q What is the energy of a photon of each of the above?

Answer 1

Following is the - complete Answer -&- Explanation: for the first four questions ( i.e. Q.1 to Q.4 ), of the given: Question Set: in....image & typed format...

Question - ANSTER: Energy of the Lights & = 2.85*10-19 J (Joule) Explanation). Geven - frequency f the Light = 4.34 x 10" 42, seet) @ We how the following formula: 2. E = h t --- - - Equation (12) Where & Planck's constant: h= 6.626 X 10 -34 5.5 (Joule. Second) Plugging in values in Equation , we would get : Energy: E = 66.626 x 10 -34 J.8) (4- 34 x 104 E = 2.85 x 10-19 J )

14 h question :- ANSWER : Frequency o 4. = 7.26 x 10' Hz. Explanation - - Given ② Wavelength : 7 = 413 nm = 4. 23 x 107 meters (m). 3 We know : velocity of light : c = 3-0 * 108 m/s. Stes Suce: 2 = % . Equation --- , playging in valeus. 1 = (3.0 x 108 m/)/(4:13 x 70*9m) - 7.26 *10*4z
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$\Rightarrow$Question - ( 3 ):

$\Rightarrow$Answer:

Wavelength of the green light:  $\lambda$ =  479 nm ( nano meters )

$\Rightarrow$Explanation:

Following is the complete Explanation: fro the above: Answer.

• Given:

1. Frequency of the Light: $\nu$ =  6.26 x 10¹⁴ Hz  OR s ^-1  
2. We know:   $\nu$ =  c / $\lambda$ ------------------------------------------------Equation - 2

• Step - 1:

​​​​​​​From Equation - 2: we get the following:

$\Rightarrow$$\lambda$ =  c / $\nu$    --------------------------------------Equation - 3

Plugging in values in Equation - 3: we would get:

$\Rightarrow$   $\lambda$ = ( 3.0 x 10⁸ m/s ) / (6.26 x 10¹⁴ Hz ) =  4.79 x 10 ^-7 m = 479 nm ( nano meters )

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$\Rightarrow$Question - (4):

$\Rightarrow$Answer:

Energy of the violet light: of Question - 2:  E =  4.81 x 10 ^-19 J  ( Joule ) ​​​​​​​

$\Rightarrow$Explanation:

Following is the complete Explanation: for the above: Answer.

• Step - 1:

​​​​​​​We know: E = h x  $\nu$  -------------------Equation - 4

$\Rightarrow$ We have found from the answer: of Question - 2:

$\nu$ = 7.26 x 10¹⁴ Hz

• Step - 2:

​​​​​​​Plugging in values in: Equation - 4: we would get the following:

$\Rightarrow$  E = ( 6.626 x 10 ^-34 J. s ) x ( 7.26 x 10¹⁴ Hz ) = 4.81 x 10 ^-19 J  ( Joule )