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A315-N thin cylindrical shell, or hoop, of radius 0.35 m is released from rest and rolls without slipping from the top to the
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Answer #1

a)

gravitational potential energy

b)

both rotational and translational energy

c)

I = (0.5) m r^2 = ( 1/2) (315 / 9.8)* 0.35^2 = 1.969 kg m^2

d)

using conservation of energy

mgh = 0.5 m v^2 + 0.5 Iw^2

mgh = 0.5 m v^2 + 0.5 (1/2) m r^2 * v^2/r^2

9.8*4.5 sin 20 = v^2

v = 3.884 m/s

rotational velocity

w = v/r = 3.884 / 0.35 = 11.1 rad/s

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