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1 Review (Figure 1) Part A If P = 200 N and the 21 kg uniform slender rod starts from rest at @= 0, determine the rods angul

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Answer #1

Referring to Fig. a,

r​​​​​​A/IC = 0.6*tan 45° = 0.6 m

TAVIY INC 0.3m 0.3m (a)- - mass center is Then; MalTC = No. 3² + 0.62 = 0.6700m Thus; (vada - We Matic = W2 (0.6700) The Mass moment of Inertia of t= 4(21) [ W, (0.6700)] ++ (0.63) wz2 - = L wa [ 9,44 9 42544 + 0,63] T2 - 5.039 w2² z = 5.04 w2

Since the rod is initially at rest, . Referring to Fig. b

W=2119.81) N P=200N (b)

And do no work,while does positive work and does negative work. When , displaces
through a horizontal distance and displaces vertically upwards
through a distance of , Fig. c.

0.3m (C)

Thus, the work done by P and W and is :-

U​​​​​​P = Ps​​​​​P = 200(0.6) = 120 J

U​​​​​​W = -Wh = - 21(9.81)(0.3 sin 45°) = - 43.7 J

T1 + \sum U 1-2 = T2

0 + [120 - 43.7] = 5.04 (w​​​​​​2)2

w​​​​​​2 = 3.89 rad/sec. Ans

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