Question

Problem 2 (10 marks) Initially unpolarized light passes in turmt esp polarizers with transmission av what is the at 0°, 30, and 60, respectively, relative to ge of the unpolarized light irradiance l rradiar 60 so*

Answer 1

Irradiation transmission by first polarizer,

I1 = Io / 2

Transmission by second polarizer,

I2 = I1cos² $\theta$

I2 = (Io / 2)cos² (30)

I2 = 0.375*Io

Transmission by third polarizer,

I3 = I2cos² $\theta$

where, $\theta$ = 60 - 30 = 30 deg

I3 = 0.375*Io cos² (30)

I3 = 0.281*Io

Irradiance of product light,

I3 / Io =  0.281*Io / Io = 0.281

I3 / Io = 28.1 %