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3. A photon with a frequency of 5.00 E14 Hz strikes a metal surface whose work function is 1.62 eV. Calculate the a) energy o
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Answer #1

can E= hf = (4.136x10-15 ev.s) *(5 x1014 Hz) = 2.07 eV (b) Kmax = E- 0 = 2.07 - 1.62 = 0.45 eV (C) 6= h fo I fo= threshold fr

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