Homework Answers
E = hc/lamda
lamda = 280 nm
E(eV) =1243/lamda(in nm)
E = 1243/280
E = 4.44 eV
Kmax = 1.44 eV
from Enstein photo electric effect equation
E = W +Kmax
4.44 = W +1.44
W = 3 eV
(b) W = hfo
3*1.6*10^-19 = 6.63*10^-34*fo
fo = 7.24*10^14 Hz
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