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What would the solubility of [Pb(OH)3]-(aq) be in 0.100 M Ba(OH)2 in the presence of excess...

What would the solubility of [Pb(OH)3]-(aq) be in 0.100 M Ba(OH)2 in the presence of excess Pb(OH)2(s)?

Ksp Ba(OH)2 = 5.0 x 10-3 Ksp Pb(OH)2 = 1.43 x 10-20 Kf [Pb(OH)3]- = 3.8 x 1014

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Answer #1

As we kuw Ks e} ৪ao4)2 = 0. [M (o] = ২x 0:| = 0 2 M SD 2t Ръoнв аg P৮ (a) + 30৮° k = 3.8x (০ ५ Lhbag30cag k+=143४।०20 Pb(oHg

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