Question

3. Pb(OH)2 (8) is amphoteric and forms the complex ion Pb(OH)/(aq) with excess OH in solution. Write the balanced equilibrium equation of Pb(OH)2 (s) in the presence of excess hydroxide. 4. A solution contains Pb(NO3)2 and Zn(NO3)2. Consult the solubility table and answer the following questions: a. NaOH (aq) is added to the solution. What precipitate (or precipitates) forms? b. Can you separate the two metal ions using NaOH? c. Nat (aq) is added to the solution. What precipitate (or precipitates) forms?! d. Can you separate the two metal ions using Nal? mage 2

Answer 1

|_ Pb(OH), + 206 = [pbconju? 4..ca, 2 precipitates form - Pb(OH), and Zn(OH)2 by no two metal ions cannot be Seperated using Nook - (ei 1 precipitate form - Pb Iz led Yes, two metal ions can be seperated using Nai (Just filter the solution as soon as pbin form).

Answer 2

3) The balanced reaction is given as Nastants Pb COM},0) + NO [faco4),] cor) The mixture of Plnog) and Zn(NO) ina aquesus! solution contains both P6?t and Zn²+ ionsson a) Both of the ins cannot be separated by wsing Norot only, anh, and Poloha vad have kip values 10424 102 and 3.0x10h En QO), + 2NaOH = Zn(OH), (s)/+ 2 Wawo.com Pb(NO3),caq) + 2NaOltcams Pb(OH)_(+ 3NaNO (any bort 6) As the ksp values are closed both P62 z n²t will form precipitate initially. But if Naoth can added become exeers both the waren precipitates will disappear as t r ee Zn cont) + 2Novoten → Na₂ [Zn (OH), I can) PG(OH), (3) + P Nadh can) - Na, [Pb (Olt),] caq). c) If NaI (49) is added then PbI is precipitated and separated because ZnI is highly soluble in water (usog/100 me at 25e). Pb(NO3)2 con 2 Na I (aq) → Pb I, (s) + + 2Nado (a) An (NO), caq) + 2NaI (ar) an I, cor) + ?NaNo (19) d) with the addition of NaI car) ;Pb I will be frecipitated and separated."