The pediatric infusion rate for potassium is 5 mEq/h. If 9 mL of a 39.2% solution...
The pediatric infusion rate for potassium is 5 mEq/h. If 9 mL of a 39.2% solution of potassium acetate (KC2H3O2) is diluted to 1 L of infusion solution, calculate the proper infusion rate in mL/h. The correct answer is 138.89 mL/h potassium acetate infusion. Please show how this question is solved.
Homework Answers
Molecular weight= Atomic mass of the element *No. of atoms of that element
( add up all the molecular weight of the elements )
Molecular weight of potassium acetete(KC2H3O2)=1*39.0983+2*12.0107+3*1.00794+2*15.9994=98.1423 g/mol
Atomic mass of
- Carbon: 12.0107
- Potassium: 39.0983
- Hydrogen: 1.00794
- Oxygen : 15.9994
Concentration of potassium acetate* volume given = Concentration of potassium acetate after dilution *1000
39.2*9=C*1000
C=352.8/1000
Concentration of potassium actetate diluted infusion solution =0.353%
Concentration of potassium actetate diluted infusion solution in 100 ml =0.353g/100ml=3.53mg/ml
The infusion rate of diluted solution with potassium infused at 5 mEq/h = (3.53*98.1423*2)/5=692.884638/5=138.58 ml/hr
(valence of potassium acetate = 2)
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