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Calculate the standard reduction potential for the reduction of aqueous vanadium(II)ion to solid vanadium given the...
Calculate the Ecell value at 298 K for the cell based on the reaction: Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s) where [Ag+] = 0.00350 M and [Cu2+] = 7.00x10-4 M. The standard reduction potentials are shown below: Ag+(aq) +e → Ag(s) E° = 0.7996 V Cu2+ (aq) + 2e -→ Cu(s) E° = 0.3419 V 2nd attempt Ecell = V
Standard reduction potentials for nickel(II) and copper(II) The standard reduction potential for a substance indicates how readily that substance gains electrons relative to other substances at standard conditions. The more positive the reduction potential, the more easily the substance gains electrons. Consider the following: Ni2+(aq)+2e−→Ni(s),Cu2+(aq)+2e−→Cu(s), E∘red=−0.230 V E∘red=+0.337 V What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate. Express your answer to three decimal places and include the...
QUESTION 49 Given that the standard reduction potentials for Copper and Barium relative to the Standard Hydrogen Electrode (SHE) are +0.34 V and 2.92 V, respectively, for the reaction: Cu2(aq) Ba(s) > Cu (s). Ba2+ (aq) calculate the change in Gibbs Free Energy associated with the the reduction of copper by barium. a. 498 kJ/mol b.-498 kJ/mol c.629 kJ/mol d. 315 kJ/mol e-249 kJ/mol
Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations provided. Then, determine if the cells are spontaneous or nonspontaneous as written. Refer to the table of standard reduction potentials (E Pt(s)Fe2+(aq) Pt2+(aq) + Fe(s) [Fe2+ [Pt2+] = 0.0023 M = 0.011 M The cell is V E = O not spontaneous. O spontaneous Cu(s)2 Ag (aq) Cu2+(aq) + 2 Ag(s) [Cu2+0.031 M [Ag*] = 0.031 M The cell is V E = O...
Consider the following cell reaction at 18°C: Ca(e)+Cu+ (aq) + Ca2+ (aq) + Cu() Calculate the standard cell potential of this cell from the standard electrode potentials, and from this, obtain AG" for the cell reaction. Calculate AF. Use these values of AN and AG to obtain AS for the cell reaction. Ca²+ (aq) +20 + Ca() --2.76 V Cu? (g) +20 + Cu(s) - 0.84 V AH;(O.*()) -- 542.8 kJ/mol AH;(Out (as)) - 64.8 kJ/mol V AG- AH- kJ...
Calculate the cell potential for the reaction below when the concentrations of ions are: [Ag+ ] = 0.010 M and [Cu2+] = 0.750 M, at 25 °C. Cu(s) + 2Ag+ (aq) --> Cu2+(aq) + 2Ag(s) Given the standard reduction potentials: Cu2+(aq) + 2e– → Cu(s) Eϴ = 0.34 V Ag+ (aq) + e– → Ag(s) Eϴ = 0.80 V (A) 0.35 V (B) 0.44 V (C) 0.46 V (D) 0.48 V (E) 0.57 V
Question 8 3.03 pts Based on the following reduction potential data, what is the AGºran for the following electrochemical cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)? Eres -0.763 V for Zn2+ (aq) + 2e - Zn(s) Ered = +0.340 V for Cu2+(aq) + 2e - Cu(s) O +106 kJ/mol O-106 kJ/mol -213 kJ/mol
Propane is used as a fuel source on many barbeque grills. What is undergoing reduction during the burning of propane while grilling? CH3CH2CH3 O2 CO2 2. Based on the reduction potential data, what is the standard cell potential for the following electrochemical cell reaction: Zn(s) + Cu2+(aq) à Zn2+(aq) + Cu(s) E°red = -0.763 V for Zn2+(aq) + 2e- à Zn(s) E°red = +0.340 V for Cu2+(aq) + 2e- à Cu(s) +1.103 V -0.423 V +0.423 V 3. What is...
Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Ca2+(aq) + 2Cut (aq) *C(s) + 2Cu2+(aq) Answer: K for this reaction would b than one. greater less Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: ca2+(aq) + 2Cu(aq)+Ca(s) + 2Cu2+(aq) kJ K for this reaction would b than one. greater Answer: less Use standard reduction potentials to calculate the standard free energy change in kJ...
Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations provided. Then, determine if the cells are spontaneous or nonspontaneous as written. Refer to the table of standard reduction potentials (E Pt(s) Fe2+(aq) Pt2+(aq) + Fe(s) Fe2+0.0050 M Pt2+10.035 M The cell is E = V not spontaneous O spontaneous. Cu(s)2 Ag(aq) Cu2t(aq) + 2 Ag(s) [Cu2+0.015 M [Ag 0.015 M The cell is E = V O spontaneous. O not spontaneous Co2+(aq)Ti3(aq)Co3t(aq) +...