1)
FeCl2 (aq) + 2 AgNO3 (aq) ------------> 2 AgCl (s) + Fe(NO3)2 (aq)
126.75 g 179.85 g
5.09 g ??
ideal yield of Fe(NO3)2 = 5.09 x 179.85 / 126.75
ideal yield of Fe(NO3)2 = 7.22 g
% yield = (actual / ideal) x 100
93.4 = (actual / 7.22) x 100
actual yield = 6.74 g
For the following reaction, 5.09 grams of iron(II) chloride are mixed with excess silver nitrate Assume...
For the following reaction, 4.96 grams of iron(II) chloride are mixed with excess silver nitrate. The reaction yields 5.72 grams of iron(II) nitrate. iron(II) chloride (aq) + silver nitrate (aq) ---> iron(II) nitrate (aq) + silver chloride (s) a. What is the theoretical yield of iron (ll) nitrate? b. What is the percent yield of iron (ll) nitrate?
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