Question

112. (3 pts) A compound containing nitrogen and oxygen is found to contain 24.5 g nitrogen and 70,0 g oxygen. Calculate the empirical formula of the compound. 13. (1 pt) Copper has a density of 8.96 g/mL. What is the volume of 2.75 g of copper? 14. (2 pts) What volume of 7.64 M HCl solution is needed to make 3.0 L of 0.150 M HCI?! 15. (2 pts) If 0.500 L of 4.45 M CuSO4 solution is diluted to 2.75 L, what is the molarity of the diluted solution? 1ALAT 1: 2010-11H00 W

I need help with the calculations. questions 12,13,14,15

Answer 1

Empirical formula forut find out holomelu by quien atemi hrow Whave long no. anol of mole cheik the element with the roof to at a omblikud valus, came has mais duide th anu - a well pull out. Memint tell you red't mulizi by any Tro so that you get a simplified no. Empirical semula formed. 112 given weight of Netugin : 245g ; Weight of oxygen melicular mecs y N = 14.9 to g. Molecular inaw suygen = 169 No. of mole of N Giren mass No. of moles of oxygen Given mass Mola, mas molantes 245 14 mole of N = 1.75 - Mole of a : 4.37 Now I haver duide up. 1.75 31.x2 = 2 a N contorne lees moles Now, we have multiply by 2 m both side to get a deered value w finall get the Emperyal formula as N2C5 wicht (13) Given density of coppe = 8:968/mL ; volume of copper 2.759 Volume 4.37 525 X253 VAAAAAAAAAAAN density - ne volumu - may PA Deneity 8.96 volume = 0.306 mL id - 14. V,=? m, = 7.64 Mice V2 = 3L , M = 0.150 mHel- we know, mv, = M₂V2 V = M2 V2 15. V, - 0. Sool ; M,- 445 Mausoy V₂ = 2.75 L M₂ ? We know mv, = M2 V₂. M : M,V, Mi 3x 0.150 7.64 ✓ = 0.05894 = 4.45 x 0.5 2.75 0.80gm Im