Molar mass of AgNO3,
MM = 1*MM(Ag) + 1*MM(N) + 3*MM(O)
= 1*107.9 + 1*14.01 + 3*16.0
= 169.91 g/mol
mass of AgNO3 = 13.1 g
mol of AgNO3 = (mass)/(molar mass)
= 13.1/1.699*10^2
= 7.71*10^-2 mol
According to balanced equation
mol of Ag2CrO4 formed = (1/2)* moles of AgNO3
= (1/2)*7.71*10^-2
= 3.855*10^-2 mol
Molar mass of Ag2CrO4,
MM = 2*MM(Ag) + 1*MM(Cr) + 4*MM(O)
= 2*107.9 + 1*52.0 + 4*16.0
= 331.8 g/mol
mass of Ag2CrO4 = number of mol * molar mass
= 3.855*10^-2*3.318*10^2
= 12.79 g
Answer: 12.8 g
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