Question

of cyclohexane and toluene have been? Comment on the overall shape ("s"-shaped vs. gradually sioping) of the distillation curve. Questions: (Attach this shoot to your notebook carbon copies for evaluation) AT 32°C, the vapor pressure of pure cyclohexane is 125 mm Hg and the vapor pressure of pure toluene is **0.2 mm Hg. Use Raoult's law to calculate the total vapor pressure at 32°C for a solution containing . mol fraction of toluene and 0.650 mol fraction of cyclohexane. (2 pts)

Answer 1

Given , At 32°C Vapour Pressure of Pure cyclohexane ( let på) = 125 mm Hg Vapour Pressure of Pure toluene ( let P2) = 46.2 mm ng mol fraction of cyclohexane (let X.) = 0.650 to luene ( let x2) = 0.350 From , Roult's law in pure P = pix + P2 x ₂ where, P= total vapour pressure of solution I P = Vapour pressure of first component . form Py = Vapour pressure of second component in - form X = mal fraction of first component X₂ = mol fraction of second component pure P = 125 x 0.650 + 40.2 x 0.350 P = 95.32 mm r Total Vapour Pressure (P) = 95.32 mm Hg.