ment Chapter 21, Problem 013 In the figure particle 1 of charge q 1.02 μC and...

Question

Question

Answer 1

Answer #1

a] At the required location, the electric field is zero.

Since the charges have the opposite sign, the required point will be on the side of one having smaller magnitude,

kq1/x^2 + kq2/[L-x]^2

1.02/x^2 -2.98/[9.4-x]^2 = 0

x = -13.25 cm answer

b] because of symmetry, y = 0 cm answer

Answer 2

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