Question

The two charges in the figure below are separated by a distance d1.50 cm, and Q+5.40 nC 880 (a) Find the electric potential at A. 7.822e3 X Your response is off by a multiple of ten. kv (b) Find the electric potential at B. 8.77e3X Your response is off by a multiple of ten. kv (c) Find the electric potential difference between B and A 949 Need Help? Read It

Answer 1

given

Q = 5.40 nC = 5.40*10^-9 C

d = 1.50 cm = 0.015 m

diagonal distance is d* = 0.015*sqrt(2) = 0.021 m.

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potential at A due to Q and 2Q,

V_A= k*Q/d + k*2Q/d

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V_A = 9*10⁹*5.40*10^-9/0.015 + 9*10⁹*2*5.40*10^-9/0.021

V_A = 7868.57 N

potential at B due to Q and 2Q,

V_B= k*2Q/d + k*Q/d

null

V_B = 9*10⁹*2*5.40*10^-9/0.015 + 9*10⁹*5.40*10^-9/0.021

V_B = 8794.28 N