Question

Used scaled ray tracing for the following scenarios and find the distance to the image, whether the image is upright or inverted, and whether the image is larger or smaller than the object. a. An object is 30 cm in front of a concave mirror with a focal length of 10 cm. b. An object is 14 cm in front of a concave mirror with a focal length of 20 cm. c. An object is 70 cm in front of a convex mirror with a focal length of -50 cm.

Used scaled ray tracing for the following scenarios and find the distance to the image, whether the image is upright or inverted, and whether the image is larger or smaller than the object. a. An object is 30 in front of a concave mirror with a focal length of 10 . b. An object is 14 in front of a concave mirror with a focal length of 20 . c. An object is 70 in front of a convex mirror with a focal length of 50 .

Answer 1

Image distance can be calculate using Mirror Formula given below

+

Image Upright or Inverted and Larger or Smaller than object says by Magnification given below

Magnification m=-v/u=-image distance/object distance

@ Given, objet distance, u = 30cm Concave minor total length, f = 10cm Image distance, v= ? using mirror formula, substibule uit values in asive equation, to = žo + * = to-go Kat:20. Wsts → VE+15 cm Imape clistance, V = + 15 cm Here Image is upright or inverted and Image is larger or smaller than object can be understood by maquification (m)" maguntication, Im = - 4 x ② matve, Image upright =-ve Image Inverted Imisi Inge enkised IMIC! Image reduced or diminished Iml=1 luge same size.

30 fubflitute u= 20cm, v = 415 cm in equation ma -= =-1151 - 5 = -0.5 m= Negative, so Image (Inverted / Imal, so Image diminished (on - Image is smaller than objet" 6 given abicht distance, u = 14 cm Concave mirnr focal length, f = 20cm Image distance, v= ? .. Image distance can se celulete by following formula I Itil I feed stanom in chove equation substitue ut values to = ty + tu dhe its to-t4 CM =2*2*5* wer. I to F** LLM = 2X LX5X7 =140 - . * v=-14.0. = -47 cm Image distance, v= - 47cm Mafuiticetion, mea ma-447) = + 3.3 m = in m= positive image is upright misi, Image is "Enlargel" cors . Image is "larger than object

© Given, object distance u= 70 cm Conver mirror toll length of = -50cm 1 Image distance, u = ? Image distence cente find out using the tollowing formule. Sulstilule u= 70 cm, f = -50 inative equation ='= tot + 525, 35 545, 35 &G 5,7 LLM = 2x5x5x7 = 350 350 v=-350 --29 cm Image distance, N=-29 cm) Here S - ve represents Inge is virtual that means it is formed behind minor Maquification, (m= - 3 m=-629) +29 - +0. m=tve positive), so Image is Upright Imiel, so Image is diminished (ors e image is smaller then objet"