Question

, bow m Problems Each problem is worth five points, except where stated 1. For 10 points I have 55 grams of an unknown metal, I place the metal in a test tube and place it in a water bath. While it was heating up in the water bath, I measured the temperature of 85 grams of water to be 23°C in a Styrofoam cup. After the metal was at 111°C for ten minutes, I poured the metal in the water in the Styrofoam cup. At equilibrium, the temperature of the mixture was 35.50C. What metal do I have and what is atomic mass rounded to the nearest whole number? Until the end, I would round to four decimal points Hint one: Hint two: I would find the specific heat of the metal first Hint three: It is not copper, I repeat it is not copper. QEMASH A+

Answer 1

mas a metal = 55g (To) Inihal Tem mahire a metal - 111c initial Tem (Tt) Final Temp = 35.56 mass of water = 85g initial Hal Temprature a wates - 23'. Tempracture final Temprature = 35-5€ e = heat realsed absorbed - Meot m= many substance ca specific heat Capacity AT= Change in Temp (TJ -T:) q = m - Heat lost by metal = Heat gainty water - (q) = 42 -1 mcat)= MCAT 9x CX ( 35.5'<- 11°C) = 859 x 4.1842 *( 35-52-233) ac 55g x C x - 75.5°C 854 x 4.184 I X 12.50 gey 1.071 J C = 854x4-184, X1258 552x75.5" specific heat capacity of metal = 1011 3 2 It can be Magnesium as literature heat capacity g maynesium = 1.02 Atomic mars = 24.30 h nearest Whole number atomic man = 24.9 mol