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12 points OSUnPhys1 22.3.P059 A charge q-2.8 C is placed at the point P shown below what is the force on q (in N)? (Assume the positive direction is to the nght. Indicate the direction with the sign of your answer.) 2.8 m 4m 1.3 uC -3.3 C
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Answer #1

Net force acting on given charge

F = force due to (-3.3uC) - force due to 1.3uC

F = k q q1 / r1^2 - k q q2 / r2^2

F = 9*10^9* 10^-12* 2.8 * ( 3.3/ 1.4^2 - 1.3/ 4.2^2)

F = 0.041 N

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