Question

please answer the following question, in particular parts b & c. I keep getting the incorrect answer. even though i have the correct equation.

The magnetic flux through the loop shown in the accompanying figure varies with time according to Фт Poe at sin(wt), where o are the direction and magnitude of the current through the 5-2 resistor at (a) t = 0; (b) t 2.17 x 10 1.5 x 103 T. m2, a = 5 s-1, and w m 120 rad/s. What 2 s, and (c) t 3.00 s? 5.0 Ω Hints Review Section 13.2 Lenz's Law for Lenz's Law, an intuitive rule for determining the direction of induced current flow. For the given description of this problem (positive direction for magnetic field is defined as pointing out of page), what does positive dm/dt mean for direction of current flow in the loop? What does negative d,m / dt mean? Take care in taking derivative of m (t) and review Section 13.1for induced voltage if needed. mA at t= 0 with 113.097 a. Current flows down 2 S. = 2.17 x 10 3 mA at with 100.245 b. Current flows up 3.00 s. mA at t with c. Current flows down

Answer 1

solution: @ cam= to é at sinut dt we know that & .-dong 4. *sinust E = -4. [et aout. (W) + sinut. (et). -d] -CU Where to = 1.5x10 37 d=55l & ws 1205 radis at to &= - 115x103 | 120k Cosios = d. sino] e E: -15 816? [ 12066 - 0]*! E = -0.56548 v Current i & = -0.56540 1 i = -113.097 mA e sign indicates current flows down. (bj at t= 2.17 X10?

E: S109 | 120 16 (as (120 x 42,746 2) - 5 sin hans ) com & - 5x16? [-120.9520 - 4.73545] x 08971 {= 0.16920 i= 33.84 mA flaws up. Part (6): at t= 35. & = -1.5x163 [ 1200 cos (12011 83 - 5 sin 120 x 3] es &= -1.5X103 [ 376.99 - sxoleis {= -1.58103 [376.99-0]*3.059x107 {= 1.72903x10-7 ] current i q = i= -1.72583x10² li= 3.459668108A ů = 34.5968159 A OR Ti= 34059 nA flows down.