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Problem 3 (20 points) A rectangular loop of length 0.35 m and total resistance 0.14 22 is pulled to the right at a constant s

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Answer #1

Let the breath of rectangular loop be X cm at instant

Magentic flux through loop= B*A*cos_theta

Theta is angle between B and A and equal to 180°

Magentic flux= B*A*cos180°= -BA

A=0.35*X

Magentic flux,= -B*0.35*X

Emf = - d(magnetic flux)/dT

Emf= -d(-B*0.35*X)/dT

Emf= B*0.35*dX/dT = B*0.35*V

dX/dT= 16cm/sec = 16*10^-2 m/sec

Emf= B*0.35*16*10^-2=2*0.35*16*10^-2

Emf= 0.7*16*10^-2= 11.2*10^-2 = 0.112 volts

B) When loop is coming out of magentic field the magnetic flux through loop is decreasing By lenz law the direction of Induced emf will take place in such a way that it will oppose the decrease in magentic flux or compensate the Loss in flux

Which is by Inducing a clockwise current and due to this a Magentic field will create into the plane of paper and a Force act on a length (inside magentic field) towards left to oppose the movement

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