Question

3. A 0.650- m long metal bar is pulled to the right at a steady 5.0 m/s perpendicular to a uniform, 0.750 T magnetic field. The bar rides on parallel metal rails connected through a 25.0 Ohm resistor. (1) Calculate the magnitude of the emf induced in the circuit (2) Calculate the current in the circuit and show its direction. (3) Which point has a higher potential? Explain it based on (6) Magnetic force on the charges in a moving bar and (ii) Faraday's - Lenz's Law. x xa x B * x 46 x

Answer 1

solt Given deler Length of the metal bor (L) = 0.650m rebcity (W) 250ml magretic field CB)20-7507 Resistor CR) = 25.01. of The the magnitude the emf Circuit inducted in E: BxLXV -0.750 0.650 x 5.0 2.4375 volt. 1. The magnitude of the emt inducted in the cercent E, 2.4-315 x from the ohn's law, the current in the circuit (I) = I, 2.4375 25-0 0.0975 Amps I The Current in the circuit (II)2 00975 A Counter clockwise I direction. 9 i magnetic tace duerto on the charges in a moving bar ² = qux Where = velity, q. Chege on the bar, B2 magnetic fick. Here, the negretic tirce poindy upword current in the clockwise direction, (2) magnetic flux Og has incrossing magnitude. - . By Faceday's law, emf Exo in the direction of the current is counter Clockwise According to the Lenz's low, the induced Cworent develops to oppose the change in nagretic flux. The thux is increasing. The induced cwerend sets in Counter clockwise direction,