Question

A 0.344 m long metal bar is pulled to the left by an applied force F. The bar rides on parallel metal rails connected through a 44.1 2 resistor, as shown in the following figure(Figure 1), so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform 0.602 T magnetic field that is directed out of the plane of the figure. 

Part A 

At the instant when the bar is moving to the left at 5.90 mn/'s, is the induced current in the circuit clockwise or counterclockwise?

 clockwise 

counterclockwise

Part B 

At the instant when the bar is moving to the left at 5.90 m/s, what is the rate at which the applied force is doing work on the bar?

Answer 1

A)

Counterclockwise

B)

Power, P = B^2 l^2 v^2/R

P = 0.602^2 x 0.344^2 x 5.90^2/44.1

P = 0.034 W

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