Using this table of ionization constants, calculate the overall equilibrium constant, Koval CH,COOH(aq) + S?-(aq) =...

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Answer 1

Answer #1

C6H5COOH(aq) + S^2- (aq) <------------> C6H5COO^- (aq) + HS^- (aq)

The rate of forward reaction = Kf[C6H5COO]{S^2-]

The react of reverse reaction = Kb[C6H5COO^-][HS^-]

At equilibrium rate of forward reaction is equal to rate of reverse reaction

forward reaction = rate of reverse reaction

Kf[C6H5COO]{S^2-] = Kb[C6H5COO^-][HS^-]

Kf/Kb = [C6H5COO^-][HS^-]/[C6H5COO]{S^2-]

Koverall = [C6H5COO^-][HS^-]/[C6H5COO]{S^2-] [K overall = kKf/Kb]

Answer 2

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