Using this table of ionization constants, calculate the overall equilibrium constant, ?overall, for the reaction.
HF(aq)+CO3(aq)↽−−⇀F(aq)+HCO3(aq)
HF + H2O ----> H3O+ + F- Ka1 = 6.6 * 10-4 --------(1)
and HCO3- + H2O ----> H3O+ + CO32- Ka2 = 4.8* 10-11
so, H3O+ + CO32- -------> HCO3- + H2O K = 1/Ka2 -----------(2)
adding both of equation
HF + CO32- -------> HCO3- + F-
Keq = Ka1 /Ka2
= 1.375 * 107
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