first mixing two solutions
M = (M1V1 + M2V2 / V1+V2)
M = (0.250 x 125) + (0.200 x 175) / 125 + 175
M = 31.25 + 35 / 300
M = 0.22 M
now this solution is diluting
M1V1 = M2V2
M1 = 0.22 M , V1 = 300 mL
M2 = ? , V2 = 500 mL
M2 = (M1V1 / V2)
M2 = (0.22 x 300 / 500)
M2 = 0.132 M
answer = 0.132 M
C | UUI 18. A 125 mL solution of0.250 M Na2SO, and a 175 mL solution...
a. v.0 e. 0.900 M 18. A 125 mL solution of 0.250 M Na2SO4 and a 175 mL solution of0.200 M Na3PO4 are mixed, and the resulting solution is diluted to 500.0 mL. Determine the concentrations of all ions in this solution in units of molarity Answer: [Na]= 0.335 M; [SO 0.0625 M; [PO= 0.0700 M is combined with 10.00 mL of a 0.0750
29. If 123 mL of a 1.1 M glucose solution is diluted to 500.0 ml what is the molarity of the diluted solution? MISSED THIS? Read Section 5.2; Watch KCV 5.2, IWE 5.3
29. If 123 mL of a 1.1 M glucose solution is diluted to 500.0 ml, what is the molarity of the diluted solution? MISSED THIS? Read Section 5.2; Watch KCV 5.2, IWE 5.3
29. If 123 mL of a 1.1 M glucose solution is diluted to 500.0 ml, what is the molarity of the diluted solution? MISSED THIS? Read Section 5.2; Watch KCV 5.2, IWE 5.3
8. A solution is made by dissolving 12.3 grams of calcium nitrate in enough water to form 500.0 mL of solution. sve (a) Calculate the molarity (M) of the resulting solution. (4) (b) What is the molarity of the nitrate ion, [NO3-), for the solution? (1) 9. What volume of 6.0 M HCl would need to be diluted with water to form 125 mL of 0.50 M HCI? (2) mivi
dilution
If I add 25 mL of water to 125 mL of a 0.15 M NaOH solution, what will the molarity of the diluted solution be? (Your answer should be written as 0.XXX with no units) Question 2 0.2 pts If I add water to 100 mL of a 0.15 M NaOH solution until the final volume is 150 mL, what will the molarity of the diluted solution be? (Your answer should be written as 0XXX with no units) Question...
erksheet 7-Rey 10 A 10.0 mL sample of sodium chioride solution that has a mass of 16.78 g is placed in an Solutions evaporating dish and evaporated to dryness. The residue has a mass of 6.55 g. Calculate the following concentrations for the NaCl solution mass/mass (m/m) percent mass/volume (m/v) percent malarity A 4.00 % (g/mL) KI solution has a volume of 65.0 mL. How many grams of KI are in the sample? How many grams of a 35% (...
5.00 mL of a solution containing a monoprotic acid was placed in a 100-mL volumetric flask, diluted to the mark with deionized water and mixed well. Then, 25.00 mL of this diluted acid solution was titrated with 0.08765 M NaOH. 9.23 mL of NaOH was required to reach the endpoint. a. What does the term monoprotic mean? b. Determine the molar ratio between the acid and NaOH. c. Calculate the moles of NaOH used in this titration. d. Calculate the...
Experiment 9 Determinations of Concentrations of Colored som Prelaboratory Exercises 1. If a 15.0 mL solution of 2.5 M NaCl is diluted to a volume of 100 mL (1.00 what is the molarity (M) of the diluted solution? Show all your steps with S diluted to a volume of 100 mL (1.00 X 10mL), 3. What is the molarity of a solution prepared by dissolving 0.450 g of HNO, in 300 mL (3.00 X 10 mL) of water? Show all...
Consider 125 grams of potassium carbonate dissolved in water to make 775 mL of solution. Identify the correct concentrations for the species below. Consider 125 grams of potassium carbonate dissolved in water to make 775 mL of solution. Identify the correct concentrations for the species below. Concentration (in M) of carbonate ions Answer 1 Choose...(2.34) (0.00234) (0.585) (1.17) (0.00117) (3.51) Concentration (in M) of potassium ions Answer 2 Choose...(2.34) (0.00234) (0.585) (1.17) (0.00117) (3.51) Concentration (in M) of potassium carbonate...