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C | UUI 18. A 125 mL solution of0.250 M Na2SO, and a 175 mL solution of 0.200M Na3PO4 are mixed, and the resulting solution i
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Answer #1

first mixing two solutions

M = (M1V1 + M2V2 / V1+V2)

M = (0.250 x 125) + (0.200 x 175) / 125 + 175

M = 31.25 + 35 / 300

M = 0.22 M

now this solution is diluting

M1V1 = M2V2

M1 = 0.22 M , V1 = 300 mL

M2 = ? , V2 = 500 mL

M2 = (M1V1 / V2)

M2 = (0.22 x 300 / 500)

M2 = 0.132 M

answer = 0.132 M

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