a. v.0 e. 0.900 M 18. A 125 mL solution of 0.250 M Na2SO4 and a...

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Answer 1

Answer #1

(na, sou] = 0.25 M, 125 ml n Na2SO4 = (0:25x125) = 31.25 mme? Nat = 2x31.25 = 62.50mmol soi? = 31.25 mmol (Naz Pou]= 0.2m, 17

Answer 2

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