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2. ANOVA Table (7 points) 2a. Study the following ANOVA summary table. Provide the missing information for the cells designat

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2a )

Source SS df MS F F-critical
Between 550-125=425 14 \frac{425}{14}=30.36 \frac{30.36}{15.625}=1.943 3.237
Within 125 22-14=8 \frac{125}{8}=15.625
Total 550 22

F critical value = 3.237............by using F critical value table or by using Excel command =FINV(0.05,14,8)

2b) F test statistic = 1.943 < F critical value = 3.237

Therefore, we fail to reject H0 at  0.05

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