Question

The results of the study are presented in the following data table. All scores are times necessary to complete the paper-folding task, recorded in seconds Noise Type White Noise Participant Classical Music Nature Sounds Participant Totals A n - 5 B 3.43 3.34 3.76 3.65 3.53 с D 3.56 3.91 3.65 4.21 4.16 3.11 3.33 3.79 3.12 3.43 P 10.10 P = 10.58 P=11.20 P = 10.98 P = 11.12 k3 N=15 G-53.98 2X2 - 195.7798 E T = 17.71 SS = 0.1127 T = 19.49 SS=0.3419 T = 16.78 SS -0.3108 The three treatments in the experiment define three populations of interest. You use an ANOVA to test the hypothesis that the three population means are equal, Present the results of your analysis in the following ANOVA table by entering the missing of values and selecting the correct values for the missing SS, MS, and F entries. (Note: For best results, retain at least two additional decimal points throughout your calculations. Depending on the order in which you do these calculations and the number of digits you retain, you may find slight rounding differences in the last digit between your answers and the answer choices.) MS df F SS ANOVA Table Source Between treatments Within treatments Between subjects Error 0.0638 0.0694

Answer 1

Applying two way ANOVA(from excel: data-data analysis: without replication)

Source	SS	df	MS	F
Bwtween treatment	0.7585	2	0.3792	6.2226
within treatment	0.7653	12	0.0638
between subjects	0.2777	4	0.0694
Error	0.4876	8	0.0609
Total	1.5238	14

the critical F =8.65

the null hypothesis is not rejected,

You can conclude that noise type affects special reasoning