Question

The following table summarizes the results of a study on SAT prep courses, comparing SAT scores of students in a private prep

1 0
Add a comment Improve this question Transcribed image text
Answer #1

This problem is the ANOVA of one way classification. We have to derive the sum of squares with the help of basic summary values.

rand Tot 6 D s367000 3543000- A NoUA table Sourca dt S3 3 13 &ooD MAR:42000 turthin 3627 ooo ds MSE 2 enlaTn ANOVA /.tko F-Sta 犬ㅅ 60 e is TKu Yato Variane and tha within-ttman Naance

Add a comment
Know the answer?
Add Answer to:
The following table summarizes the results of a study on SAT prep courses, comparing SAT scores...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • CENGAGE I MINDTAP Complete: Chapter 12 Problem Set 6. ANOVA calculations and rejection of the nul...

    CENGAGE I MINDTAP Complete: Chapter 12 Problem Set 6. ANOVA calculations and rejection of the null hypothesis Click here to learn ollowing table summarizes the results of a study on SAT prep courses, com private preparation class, table to answer the remaining questions aring SAT scores of students in a a high school preparation class, and no preparation class. Use the information from the Sum of Squares (ss) 132,750.00 147,500.00 162,250.00 60 645 No prep class 625 Using the data...

  • Attempts: Average: /12 ANOVA calculations and rejection of the null hypothesis Aa Aa The followin...

    Please answer all parts Attempts: Average: /12 ANOVA calculations and rejection of the null hypothesis Aa Aa The following table summarizes the results of a study on SAT prep courses, comparing SAT scores of students in a private preparation class, a high school preparation class, and no preparation class. Use the information from the table to answer the remaining questions. Number of Sum of Observations Sample Mean Squares (SS) 650 645 625 Treatment Private prep class High school prep class...

  • Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatm...

    Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatment, Error, and Total Which of the following reasons best explains why the within-treatments sum of squares is sometimes referred to as the "error sum of squares"? O Differences among members of the sample who received the same treatment occur when the researcher O Differences among members of...

  • In some ANOVA summary tables you will see, the labels in the first (source) column are Treatment, Error, and Total Whic...

    In some ANOVA summary tables you will see, the labels in the first (source) column are Treatment, Error, and Total Which of the following reasons best explains why the within-treatments variance is sometimes referred to as the error variance"? O The within-treatments variance measures random, unsystematic differences within each of the samples assigned to each of the treatments. These differences are not due to treatment effects because everyone within each sample received the same treatment; therefore, the differences are sometimes...

  • 4. ANOVA calculations and rejection of the null hypothesis The following table summarizes the results of...

    4. ANOVA calculations and rejection of the null hypothesis The following table summarizes the results of a study on SAT prep courses, comparing SAT scores of students in a private preparation dlass, a high school preparation dlass, and no preparation dass. Use the information from the table to answer the remaining questions. Number of Observations Treatment Sample Mean Sum of Squares (SS) Private prep dlass 40 610 97,500.00 High school prep class 40 600 101,400.00 No prep class 40 590...

  • The results of the study are presented in the following data table. All scores are times...

    The results of the study are presented in the following data table. All scores are times necessary to complete the paper-folding task, recorded in seconds Noise Type White Noise Participant Classical Music Nature Sounds Participant Totals A n - 5 B 3.43 3.34 3.76 3.65 3.53 с D 3.56 3.91 3.65 4.21 4.16 3.11 3.33 3.79 3.12 3.43 P 10.10 P = 10.58 P=11.20 P = 10.98 P = 11.12 k3 N=15 G-53.98 2X2 - 195.7798 E T = 17.71...

  • For either independent-measures or repeated-measures designs comparing two treatments, the mean difference can be evaluated with...

    For either independent-measures or repeated-measures designs comparing two treatments, the mean difference can be evaluated with either at test or an ANOVA. The two tests are related by the equation F=12. The following data are from a repeated-measures study: Person Difference Scores 3 I 4 2 3 7 M = 4.00 T = 16 SS = 14 Treatment II 7 11 6 10 M 8.50 T-34 SS = 17 3 3 Mo 4.50 SS = 27.00 Use a repeated-measures t...

  • A student ran a between-subjects experiment comparing three treatments for depression: cognitive-behavioral therapy (CBT), client-centered therapy...

    A student ran a between-subjects experiment comparing three treatments for depression: cognitive-behavioral therapy (CBT), client-centered therapy (CCT), and a no-treatment condition. Subjects were randomly assigned to the experimental condi- tion. After a sufficient duration on these treatments, the difference in subject’s depression scores pre/post study were measured using a valid depression assessment instrument. The data are summarized in the tables below. Conduct a Oneway ANOVA with α = 0.05 by first completing the values in the lower table, then using...

  • Please help with the following multiple choice 1. In the one-way ANOVA where there are k...

    Please help with the following multiple choice 1. In the one-way ANOVA where there are k treatments and n observations, the degrees of freedom for the F-statistic are equal to, respectively: a. n and k. b. k and n. c. n − k and k − 1. d. k − 1 and n − k. 2. In ANOVA, the F-test is the ratio of two sample variances. In the one-way ANOVA (completely randomized design), the variance used as a numerator...

  • Exhibit 13-7 The following is part of an ANOVA table, which was the result of three...

    Exhibit 13-7 The following is part of an ANOVA table, which was the result of three treatments and a total of 18 observations (6 observations per sample). Source of Variation Sum of Mean F Degrees of Freedom Squares Square Between treatments 64 Within treatments (Error) 96 Total 1) Refer to Exhibit 13-7. The number of degrees of freedom corresponding to between treatments is 2) The number of degrees of freedom corresponding to within treatments is 3) The mean square between...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT